Time dilation

A forum set up for physics questions from students in the courses PHYS1121, 1131, 1221 and 1331 at the University of New South Wales. It is intended for questions that cannot readily be answered in class,
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Duncan
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Joined: Tue Mar 20, 2012 6:21 pm

Re: Time dilation

Post by Duncan »

Hello Joe,
Sorry but I don't follow you, the animation shows Zoe"s and Jasper's view of the pulse, heading in different directions
Duncan.
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joe
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Re: Time dilation

Post by joe »

True. The relative direction changes in a different frame. A crosswind when you are stationary at the lights becomes a cross-headwind as soon as you start pedalling. (The vector addition is more complicated for light, of course, but the principle is the same.)

But the pulses hit the same mirror, which is stationary in one frame but moving in the other (hence the different direction).

Joe
Duncan
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Joined: Tue Mar 20, 2012 6:21 pm

Re: Time dilation

Post by Duncan »

G'day Joe,
Don't understand your answer, doesn't the animation show the observers view of the pulse, going in different directions?
Duncan.
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joe
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Re: Time dilation

Post by joe »

Yes. True. The relative direction changes in a different frame.

But the pulses hit the same mirrors for both observers, because for one observer the mirrors are moving.

Joe
Duncan
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Re: Time dilation

Post by Duncan »

Hi Joe,
A different question. Convert Zoe's and Jasper's transportation to Collins Class, and run the experiment underwater. Reduce Zoe's speed in proportion to the reduced underwater light speed. What will the amount of time dilation be relative to the dry version?
Cheers,
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joe
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Re: Time dilation

Post by joe »

In the first case, the dilation factor is 1/sqrt(1-v1^2/c^2)
In the second case, because you impose the condition v2 = v1/n,
the new dilation factor is 1/sqrt(1-v2^2/c^2) = 1/sqrt(1-v1^2/n^2c^2)
so the ratio is sqrt((1-v1^2/c^2)/(1-v1^2/n^2c^2)

Joe
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